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Table.SplitColumn

使用指定的拆分器函数将指定的列拆分为一组其他列。

Syntax

Table.SplitColumn(
table as table,
sourceColumn as text,
splitter as function,
optional columnNamesOrNumber as any,
optional default as any,
optional extraColumns as any
) as table

Remarks

使用指定的拆分器函数将指定的列拆分为一组其他列。

  • table: 包含要拆分的列的表。
  • sourceColumn: 要拆分的列的名称。
  • splitter: 用于拆分列的拆分器函数(例如,Splitter.SplitTextByDelimiterSplitter.SplitTextByPosition)。
  • columnNamesOrNumber: 要创建的新列名列表或新列数。
  • default: 替代当没有足够的拆分值来填充所有新列时使用的值。此参数的默认值为 null
  • extraColumns: 指定如果拆分值的数量可能多于新列的数量时该怎么做。可以将 ExtraValues.Type 枚举值传递给此参数。默认值为 ExtraValues.Ignore

Examples

Example #1

将姓名列拆分为名字和姓氏。

let
Source = #table(type table[CustomerID = number, Name = text, Phone = text],
{
{1, "Bob White", "123-4567"},
{2, "Jim Smith", "987-6543"},
{3, "Paul", "543-7890"},
{4, "Cristina Best", "232-1550"}
}),
SplitColumns = Table.SplitColumn(
Source,
"Name",
Splitter.SplitTextByDelimiter(" "))
in
SplitColumns

Result:

#table(type table[CustomerID = number, Name.1 = text, Name.2 = text, Phone = text],
{
{1, "Bob", "White", "123-4567"},
{2, "Jim", "Smith", "987-6543"},
{3, "Paul", null, "543-7890"},
{4, "Cristina", "Best", "232-1550"}
})

Example #2

将姓名列拆分为名字和姓氏,然后重命名新列。

let
Source = #table(type table[CustomerID = number, Name = text, Phone = text],
{
{1, "Bob White", "123-4567"},
{2, "Jim Smith", "987-6543"},
{3, "Paul", "543-7890"},
{4, "Cristina Best", "232-1550"}
}),
SplitColumns = Table.SplitColumn(
Source,
"Name",
Splitter.SplitTextByDelimiter(" "),
{"First Name", "Last Name"})
in
SplitColumns

Result:

#table(type table[CustomerID = number, First Name = text, Last Name = text, Phone = text],
{
{1, "Bob", "White", "123-4567"},
{2, "Jim", "Smith", "987-6543"},
{3, "Paul", null, "543-7890"},
{4, "Cristina", "Best", "232-1550"}
})

Example #3

将姓名列拆分为名字和姓氏,重命名新列,并使用 "-无条目-" 填充任何空白。

let
Source = #table(type table[CustomerID = number, Name = text, Phone = text],
{
{1, "Bob White", "123-4567"},
{2, "Jim Smith", "987-6543"},
{3, "Paul", "543-7890"},
{4, "Cristina Best", "232-1550"}
}),
SplitColumns = Table.SplitColumn(
Source,
"Name",
Splitter.SplitTextByDelimiter(" "),
{"First Name", "Last Name"},
"-No Entry-")
in
SplitColumns

Result:

#table(type table[CustomerID = number, First Name = text, Last Name = text, Phone = text],
{
{1, "Bob", "White", "123-4567"},
{2, "Jim", "Smith", "987-6543"},
{3, "Paul", "-No Entry-", "543-7890"},
{4, "Cristina", "Best", "232-1550"}
})

Example #4

将姓名列拆分为名字和姓氏,然后重命名新列。由于值的数量可能多于可用列的数量,因此请将姓氏列设为包含名字后所有值的列表。

let
Source = #table(type table[CustomerID = number, Name = text, Phone = text],
{
{1, "Bob White", "123-4567"},
{2, "Jim Smith", "987-6543"},
{3, "Paul Green", "543-7890"},
{4, "Cristina J. Best", "232-1550"}
}),
SplitColumns = Table.SplitColumn(
Source,
"Name",
Splitter.SplitTextByDelimiter(" "),
{"First Name", "Last Name"},
null,
ExtraValues.List)
in
SplitColumns

Result:

#table(type table[CustomerID = number, First Name = text, Last Name = text, Phone = text],
{
{1, "Bob", {"White"}, "123-4567"},
{2, "Jim", {"Smith"}, "987-6543"},
{3, "Paul", {"Green"}, "543-7890"},
{4, "Cristina", {"J.", "Best"}, "232-1550"}
})

Category

Table.Transformation